Vulcanization-induced failed lead-acid storage battery repair method

Vulcanization-induced failed lead-acid storage battery repair method

  • CN 102,522,601 A
  • Filed: 11/21/2011
  • Published: 06/27/2012
  • Est. Priority Date: 11/21/2011
  • Status: Active Application
First Claim
Patent Images

1. the lead acid accumulator restorative procedure that lost efficacy based on sulfuration is characterized in that may further comprise the steps:

  • (1) fault range estimation;

    the battery of removing outward appearance breakage, leakage, distortion or other hard fault through range estimation;

    (2) detect;

    use universal instrument to do further to detect, reject short circuit, battery opens circuit;

    (3) precharge;

    the charging method by battery producer provides is carried out once conventional precharge, satisfies the condition that is full of of nominal up to battery;

    (4) pulp of pole plate active matter is judged;

    the electrolyte that extracts after charging is observed, and whether pulp comes off to judge plate active material;

    (5) inject diluted acid or repair liquid;

    above-mentioned steps judges that back as no pulp come off, and takes the diluted acid that adds diluted acid or be mixed with repair liquid to repairing battery, and addition to the utmost point group surface is the rich solution state, and sour density is 0.8g/cm 3To 1.0 g/cm 3Between;

    (6) battery leaves standstill;

    after above-mentioned steps was handled, battery left standstill, and time of repose was greater than 2 hours;

    (7) record initial capacity;

    detect initial voltage of battery and record, detect battery initial capacity and record;

    (8) record discharge time and the overdischarge time;

    after the normalized current that dispatches from the factory by this battery is discharged to the final voltage of this battery, continue to be discharged to final voltage again 0.5 times, write down the overdischarge time;

    Continue to be discharged to 0.5 times of final voltage again with 0.5 times of normalized current again;

    (9) confirm to repair charging capacity and discharge and recharge flow process;

    this battery was left standstill more than 1 hour;

    According to step

         7),

         8) middle three data initial voltages, initial capacity and the overdischarge time of writing down;

    Confirm the charging capacity that this battery is repaired, repair according to different capacityConcrete classification restorative procedure is following;

    The charging capacity classification of (one) battery being repaired is classified by 10% of this battery standard capacity, and being divided into is ten grades, and the charging capacity computing formula that battery is repaired is following;

    Charging capacity=(normal capacity-initial capacity that battery to be repaiied dispatches from the factory) * 1.5+ initial capacity(2) flow process of battery reparationNormal capacity when the C representative battery of below describing to be repaiied dispatches from the factory, h representative hour,Capacity=discharge time * standard discharging current1) initial capacity >

    =C, the reparation flow process doesGet the constant voltage charge voltage of this battery,, carry out modified constant-voltage charge 12h, repair and finish with the electric current of 0.1C;

    2) <

    C, the reparation flow process does 90%C≤

    initial capacityWith the electric current of 0.1C, constant current charge 6h leaves standstill 1h,Get the constant voltage charge voltage of this battery,, carry out constant voltage and current limiting and fill 12h, repair and finish with the electric current of 0.08C;

    3) <

    90%C, the reparation flow process does 80%C≤

    initial capacityWith the electric current of 0.1C, constant current charge 4h leaves standstill 0.5h,Use the electric current of 0.08C again, constant current charge 2h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 6h repairs and finishes;

    4) <

    80%C, the reparation flow process does 70%C≤

    initial capacityWith the electric current of 0.15C, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 6h repairs and finishes;

    5) <

    70%C, the reparation flow process does 60%C≤

    initial capacityWith the electric current of 0.15C, constant current charge 4h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.08C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 3h repairs and finishes;

    6) <

    60%C, the reparation flow process does 50%C≤

    initial capacityWith the electric current of 0.15C, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.08C again, constant current charge 4h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 6h repairs and finishes;

    7) 40%C≤

    initial capacity <

    50%C or initial voltage>

    10% nominal voltage, the reparation flow process doesWith the electric current of 0.1C, constant current charge 1h leaves standstill 0.5h,Use the electric current of 0.15C again, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.08C again, constant current charge 4h leaves standstill 1h,Use the electric current of 0.08C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 10h repairs and finishes;

    8) 30%C≤

    initial capacity <

    40%C or initial voltage>

    15% nominal voltage, the reparation flow process doesWith the electric current of 0.05C, constant current charge 2h uses the electric current of 0.1C again, and constant current charge 2h leaves standstill 0.5h,Use the electric current of 0.15C again, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 8h repairs and finishes;

    9) <

    30%C or initial voltage≤

    90% nominal voltage, the reparation flow process does 20%C≤

    initial capacityWith the electric current of 0.05C, constant current charge 2h uses the electric current of 0.1C again, and constant current charge 2h leaves standstill 0.5h,Use the electric current of 0.15C again, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant-current discharge 1h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 8h repairs and finishes;

    10) <

    the reparation flow process does initial capacity for 20%C, initial voltage≤

    80% nominal voltageWith the electric current of 0.05C, constant current charge 2h uses the electric current of 0.1C again, and constant current charge 2h leaves standstill 0.5h,Use the electric current of 0.15C again, constant current charge 6h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant-current discharge 1h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 0.5h,Use the electric current of 0.1C again, constant current charge 3h leaves standstill 1h,Use the electric current of 0.05C at last, constant current charge 6h repairs and finishes.

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